SQLite – PHP

Windows 用户必须启用 php_sqlite3.dll 才能使用该扩展。自 PHP 5.3.0 起，这个 DLL 被包含在 PHP 的 Windows 分发版中。

如需了解详细的安装指导，建议查看我们的 PHP 教程和它的官方网站。

PHP 接口 API

以下是重要的 PHP 程序，可以满足您在 PHP 程序中使用 SQLite 数据库的需求。如果您需要了解更多细节，请查看 PHP 官方文档。

下面的 PHP 代码显示了如何连接到一个现有的数据库。如果数据库不存在，那么它就会被创建，最后将返回一个数据库对象。

创建表

下面的 PHP 代码段将用于在先前创建的数据库中创建一个表：

  <?php
   class MyDB extends SQLite3
   {
      function __construct()
      {
         $this->open('test.db');
      }
   }
   $db = new MyDB();
   if(!$db){
      echo $db->lastErrorMsg();
   } else {
      echo "Opened database successfully\n";
   }
   $sql =<<<EOF
      CREATE TABLE COMPANY
      (ID INT PRIMARY KEY     NOT NULL,
      NAME           TEXT    NOT NULL,
      AGE            INT     NOT NULL,
      ADDRESS        CHAR(50),
      SALARY         REAL);
EOF;
   $ret = $db->exec($sql);
   if(!$ret){
      echo $db->lastErrorMsg();
   } else {
      echo "Table created successfully\n";
   }
   $db->close();
?>

上述程序执行时，它会在 test.db 中创建 COMPANY 表，并显示下面所示的消息：

    Opened database successfully
    Table created successfully

下面的 PHP 程序显示了如何在上面创建的 COMPANY 表中创建记录：

上述程序执行时，它会在 COMPANY 表中创建给定记录，并会显示以下两行：

    Opened database successfully
    Records created successfully

SELECT 操作

下面的 PHP 程序显示了如何从前面创建的 COMPANY 表中获取并显示记录：

<?php
   class MyDB extends SQLite3
   {
      function __construct()
      {
         $this->open('test.db');
      }
   }
   $db = new MyDB();
   if(!$db){
      echo $db->lastErrorMsg();
   } else {
   }
   $sql =<<<EOF
      SELECT * from COMPANY;
EOF;
   $ret = $db->query($sql);
   while($row = $ret->fetchArray(SQLITE3_ASSOC) ){
      echo "ID = ". $row['ID'] . "\n";
      echo "NAME = ". $row['NAME'] ."\n";
      echo "ADDRESS = ". $row['ADDRESS'] ."\n";
      echo "SALARY =  ".$row['SALARY'] ."\n\n";
   }
   echo "Operation done successfully\n";
   $db->close();
?>

上述程序执行时，它会产生以下结果：

    Opened database successfully
    ID = 1
    NAME = Paul
    ADDRESS = California
    SALARY =  20000
    ID = 2
    NAME = Allen
    ADDRESS = Texas
    SALARY =  15000
    ID = 3
    NAME = Teddy
    ADDRESS = Norway
    SALARY =  20000
    ID = 4
    NAME = Mark
    ADDRESS = Rich-Mond
    SALARY =  65000
    Operation done successfully

下面的 PHP 代码显示了如何使用 UPDATE 语句来更新任何记录，然后从 COMPANY 表中获取并显示更新的记录：

上述程序执行时，它会产生以下结果：

    Opened database successfully
    1 Record updated successfully
    ID = 1
    NAME = Paul
    ADDRESS = California
    SALARY =  25000
    ID = 2
    NAME = Allen
    ADDRESS = Texas
    SALARY =  15000
    ID = 3
    NAME = Teddy
    ADDRESS = Norway
    SALARY =  20000
    ID = 4
    NAME = Mark
    SALARY =  65000

DELETE 操作

  <?php
   class MyDB extends SQLite3
   {
      function __construct()
      {
         $this->open('test.db');
      }
   }
   $db = new MyDB();
   if(!$db){
      echo $db->lastErrorMsg();
   } else {
      echo "Opened database successfully\n";
   }
   $sql =<<<EOF
      DELETE from COMPANY where ID=2;
EOF;
   $ret = $db->exec($sql);
   if(!$ret){
     echo $db->lastErrorMsg();
   } else {
      echo $db->changes(), " Record deleted successfully\n";
   }
   $sql =<<<EOF
      SELECT * from COMPANY;
EOF;
   $ret = $db->query($sql);
   while($row = $ret->fetchArray(SQLITE3_ASSOC) ){
      echo "ID = ". $row['ID'] . "\n";
      echo "NAME = ". $row['NAME'] ."\n";
      echo "ADDRESS = ". $row['ADDRESS'] ."\n";
      echo "SALARY =  ".$row['SALARY'] ."\n\n";
   }
   echo "Operation done successfully\n";
   $db->close();
?>

上述程序执行时，它会产生以下结果：

    Opened database successfully
    1 Record deleted successfully
    ID = 1
    NAME = Paul
    ADDRESS = California
    SALARY =  25000
    ID = 3
    NAME = Teddy
    ADDRESS = Norway
    SALARY =  20000
    ID = 4
    NAME = Mark
    ADDRESS = Rich-Mond
    SALARY =  65000