7.4 切片重组(reslice)
其中 作为切片初始长度而 capacity
作为相关数组的长度。
这么做的好处是我们的切片在达到容量上限后可以扩容。改变切片长度的过程称之为切片重组 reslicing,做法如下:slice1 = slice1[0:end]
,其中 end 是新的末尾索引(即长度)。
将切片扩展 1 位可以这么做:
sl = sl[0:len(sl)+1]
示例 7.11
输出结果:
The length of slice is 1
The length of slice is 2
The length of slice is 3
The length of slice is 4
The length of slice is 5
The length of slice is 8
The length of slice is 9
The length of slice is 10
Slice at 0 is 0
Slice at 1 is 1
Slice at 2 is 2
Slice at 3 is 3
Slice at 6 is 6
Slice at 7 is 7
Slice at 8 is 8
Slice at 9 is 9
另一个例子:
a = a[0:4] // ref of subarray {5,6,7,8} - len(a) is now 4 but cap(a) is still 5
问题 7.7
1) 如果 a 是一个切片,那么 a[n:n]
的长度是多少?
2) a[n:n+1]
的长度又是多少?